The lines 2x + 5y – 25 = 0 and 5x + 4y – 20 = 0 are diameter of a circle. Find
the radius of the circle which passes through the point (3, 4(
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2x−3y=5−−−−(1)
3x−4y=7−−−−(2)
are diameter of circle so, point of intersection is centre of circle.
from (1) & (2), x=1,y=−1
∴ area of circle is 154
=πr2=154
r2=227×154
=27×14
r2=49
r=7
∴ Equation of circle with centre (1,−1) and radius 7 units
(x−1)2+(y+1)2=72
⇒x2+y2−2x+2y−47=0
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