The lines BD and CE intersect at 0. The line OA makes an angle of 30 with OD angle COB = 80° Find Angle 1, 2,3
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1
30 + ∠2 = 80 ... (vertically opposite angles)
∠2 = 50
Now,
30 + ∠2 + ∠3 = 180 ... (since they form a straight line)
∠3 = 180 - 80
∠3 = 100
Now,
∠1 = ∠3 = 100 ... (vertically opposite angles)
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Answered by
0
Step-by-step explanation:
3 + 80 = 180
3 = 180 - 80
3 = 100
1 = 3 (Vertically opposite)
1 = 100
1 + 30 + 2 = 180
100 + 30 + 2 = 180
130 + 2 = 180
2 = 180 - 130
2 = 50
Therefore,
1 = 100
2 = 50
3 = 100
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