The lines represented by 3x + y - 12 = 0 and x - 3y + 6 = 0 intersects the y-axis
at
a) (0, - 2) and (0, 12)
c) (0, - 2) and (0, -12)
b) (0, 2) and (0, -12)
d) (0, 2) and (0,12)
Answers
Answer:
c is the correct answer
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The correct answer is option d) (0, 2) and (0, 12).
Given:
The equations of two lines: 3x + y - 12 = 0 and x - 3y + 6 = 0.
To Find:
The point where these lines intersect the y-axis.
Solution:
The general equation of a lines is given by ax + by + c = 0.
Here, we have the equations of two lines:
3x + y - 12 = 0 ...................(I)
and x - 3y + 6 = 0 ...................(II)
We are asked to find the co-ordinates where these lines meet the y-axis.
When these two equations meet the y-axis, their x co-ordinate is 0.
So we substitute x = 0 in each of the given equations to find their respective x co-ordinates.
On substituting x = 0 in equation (I) we have:
3(0) + y - 12 = 0
⇒ y = 12.
∴ The line 3x + y - 12 = 0 meets the y-axis at (0, 12).
On substituting x = 0 in equation (II) we have:
0 - 3y + 6 = 0
⇒ 3y = 6
⇒ y = 2
∴ The line x - 3y + 6 = 0 meets the y-axis at (0, 2).
Hence, correct answer is option d) (0, 2) and (0, 12).
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