The lines representing 2x+5y-7=0 and 4x+10y-14=0 are which type of lines
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There is error in the Q. In (II) there should have been 2x - 3y = 12
5x + 3y = 9 -----(I)
2x - 3y = 12 ----- (II)
Add (I) and (II)
7x = 21
x = 3
Putting the value of x = 3 in (I) we get
5(3) +3y = 9 ⇒ 15 + 3y = 9 ⇒ 3y = 9 - 15 = -6 ⇒ y = -2
Thus, (x, y) = (3, -6).
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