Question

the lines representing 5x-4y+8=0 and 7x+6y-9=0 are ______.​

Answer 1

Answer:

5x-4y+8=0 be equation 1st  

7x+6y-9=0 be equation 2nd

solve these two equations to find the intersection point of these two equation

5x-4y=-8 be equation 1st

7x+6y=9 be equation  2nd

multiply 1st equation by 3 and multilply 2nd equation by 2 to gey the coefficient of y equal i am using elimination method to solve x and y  

5x(3) -4y(3) = -8×3

7x(2)+6y(2)  =  9×2

15x-12y=-24 equation 3rd

14x+12y=18 equation 4th

add these two equation  

15x+14x-12y+12y=-24+18

29x=-6

x=-6/29

substitute x=-6/29en equation 1st 5x-4y=-8

5(-6/29)+-4y=-8

4y=(30/29)-8

4y=(30-29×8)/29

4y=-202/29

2y=-101/29

y=-101/58  

we get the value of x and y now on representing these two line on graph i put  

these two lines intersect at point p point p is (-6/29,-101/58)

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