Question

The lines x-2y-6=0, 3x+y-4=0 ix+4y+22=0 are concurrent then | ix | = ?

Answer 1

Given : The lines  x-2y-6=0, 3x+y-4=0  , ix+4y+22=0 are concurrent

To Find :   | ix | =

Solution:

x-2y-6=0,     Eq1

3x+y-4=0      Eq2

=> eq1 + 2 Eq2

=> x - 6  + 6x  - 8 = 0

=> 7x = 14

=> x = 2

3(2) + y - 4 = 0

=> y = - 2

( 2, - 2)  is point of intersection

ix+4y+22=0

=> ix + 4(-2) + 22 = 0

=> ix  = - 14

=>| ix |  = 14

& i = -7

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