The lines x – y = 1 and 2x + y = 8 intersects at
(1, 9) (b) (9, 3) (c) (3, 4) (d) none.
Solution of 2x + 3y = 12, 2y – 1 = x is
(8, - 1) (b) ((3, 8) (c) (3, 2) (d) (1, -1).
Y = mx + c line intersects the y – axis at .
(0, m) (b) (0, c) (c) (m, 0) (d) (c, 0).
The larger of two supplementary angles exceeds the smaller
by 380. Then the angles are
710, 1080 (b) 720, 1080 (c) 1090, 710
(d) 1420, 380.
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1
Answer:
ANSWER
Solving lines x+y−2=0 and 2x−y+1=0
We get x=
3
1
⟹y=2−x=2−
3
1
=
3
5
Substitute (x,y) in ax+by−c=0
We get
3
a
+
3
5b
=c.....(i)
Substitute value of c in 2ax+3by+c=0 we get 2ax+3by+
3
a
+
3
5b
=0
⟹a(2x+
3
1
)+b(3y+
3
5
)=0 this family will always pass through x=−
6
1
,y=−
9
5
.
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