Question

The lines x – y = 1 and 2x + y = 8 intersects at
(1, 9) (b) (9, 3) (c) (3, 4) (d) none.
Solution of 2x + 3y = 12, 2y – 1 = x is
(8, - 1) (b) ((3, 8) (c) (3, 2) (d) (1, -1).
Y = mx + c line intersects the y – axis at .
(0, m) (b) (0, c) (c) (m, 0) (d) (c, 0).
The larger of two supplementary angles exceeds the smaller
by 380. Then the angles are
710, 1080 (b) 720, 1080 (c) 1090, 710
(d) 1420, 380.

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Answer 1

Answer:

ANSWER

Solving lines x+y−2=0 and 2x−y+1=0

We get x=

3

1

⟹y=2−x=2−

3

1

=

3

5

Substitute (x,y) in ax+by−c=0

We get

3

a

+

3

5b

=c.....(i)

Substitute value of c in 2ax+3by+c=0 we get 2ax+3by+

3

a

+

3

5b

=0

⟹a(2x+

3

1

)+b(3y+

3

5

)=0 this family will always pass through x=−

6

1

,y=−

9

5

.