Question

The lines x+y=5, x-y=1& Kx+2y=8
Are concurrent lines, then the value of k is??

Answer 1

we assume x+y=1 as equation 1

and x-y=2as equation 2

from 1&2

by adding

we get

x=3

y=2

substituting these values in kx+2y=8

we get

3k+2(2)=8

3k+4=8

3k=4

k=4/3