The lines x+y+7=0 and 3x-ay+6=0 are parallel then a=?
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When lines are parallel
a1/a2 = b1/b2 != c1/c2
1/3 = 1/(-a) != 7/6
1/3 = 1/(-a)
a = -3
a1/a2 = b1/b2 != c1/c2
1/3 = 1/(-a) != 7/6
1/3 = 1/(-a)
a = -3
Answered by
0
Answer:
a= -3
Step-by-step explanation:
When lines are parallel
a1/a2 = b1/b2 not equal to c1/c2
Given
x+y+7=0 => a1x+b1y+c1=0
3x-ay+6=0 => a2x+b2y+c2=0
Here,
a1=1, b1=1, c1=7
a2=3, b2=-a, c2=6
a1/a2=1/3
1/3=1/(-a) not equal to 7/6
1/3=1/(-a)
•°• a= -3
Hope it helps you
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