Biology, asked by Nawabv1675, 1 year ago

The linkage map of X-chromosome of fruit fly has 66 units with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two genes (y and b) should be [CBSE PMT 2003]
A) 100 %
B) 66 %
C) 50 %
D) 5.50 %

Answers

Answered by vivek80437
0
I have a confusion......
Answered by Anonymous
1
the answer to your question is b
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