The liquid is flowing separately through each of two pipes whose diameter are in the ratio of 2:1, if the ratio of the velocities of flow in the two pipes by 1:2, then the ratio of the amounts of the liquid flowing per sec through the pipe will be
Answers
When the liquid is flowing separately through two pipes whose diameter are in the ratio of 2:1 and the ratio of the velocities of flow in the two pipes by 1:2, then the ratio of the amounts of the liquid flowing per sec through the pipe will be 2:1 since if the ratio of velocity is 1:2 then the ratio of time will be 2:1
ANS:
Given data- (1) ratio of diameter = 2:1
(2) ratio of velocities = 1:2
we need to find ratio of FLUX- ratio amount of liquid flowing per sec
what is the formula of calculating liquid flow per second ?
= cross sectional area of pipe × velocity
= (Pi * R²) × V
now FLUX of pipe one F₁ - 2 * 1 (proportional)
F₂ - 1 * 2 (proportional
therefore ratio of flux = F₁/F₂
= 2*1/ 1*2
= 1:1 FINAL ANS