the liquids A and b are at 30 degree Celsius and 20 degree Celsius when mixed in equal masses the temperature of the mixture is found to be 26 degree Celsius that specific heat are in the ratio of
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Answer:
Ratio :- 3:2
Explanation:
Loss in temperature of one liquid is equal to the gain in temperature of another liquid.
m1.C1.ΔT1 = m2.C2.ΔT2
Given the masses are same
C1.(30−26) = C2.(26−20)
C1/C2 = 6/4
= 3/2
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