Question

The liquids x and y are mixed in the ratio of 3:2 and the mixture is sold at rs 11 per litre at a profit of 10% . if the liquid x costs rs 2 more per litre than y, the cost of x per litre is

Answer 1

The mixture is sold at 10% profit, which means that the selling price = cost price + 10% of cost price i.e., SP = 110% of cost price = 1.1*CP. 
The mixture is sold (SP) at Rs.11. Therefore, the cost price of the mixture, CP = Rs.10 
Let Rs.x be the cost of the first liquid. Therefore, cost of the second liquid = Rs.(x - 2). 
The liquids are mixed in the ratio of 3 : 2 
In 5 liters of the mixture, 3 liters will be first liquid and 2 liters will be the second liquid Therefore, cost of 5 liters of the mixture = 3x + 2(x 2) = 5 * (Cost of the 1 liter of the mixture) 3x+2x-4=50 or 5x = 54 
Therefore, x = Rs.10.80 and x-2 = Rs.8.80