Question

The list November must be subtracted from 261 to make 3 a perfect square is

Answer 1

Step-by-step explanation:

First, we will try to find the square root of the given number 5607 by using Division method.

747∣∣∣∣56¯¯¯¯¯07¯¯¯¯¯−49¯¯¯¯¯¯¯¯¯¯¯¯¯144∣∣∣∣∣707−576−−−−131¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯747|56¯07¯−49¯144|707−576_131¯

Therefore, 131 is the required least number.

Now, we will subtract the remainder i.e. 131 from the given number.

Hence, we get,

(5607−131)=5476(5607−131)=5476