Math, asked by narinderkaur610, 14 hours ago

The list price of a watch is Rs.4000. It is available either at 25% flat discount or at successive discounts of 15% and 12%. Calculate the better offer and the amount paid in the second offer.​

Answers

Answered by Souvickpal
2

Answer:

THE BETTER OFFER IS 25% OFF AND THE AMOUNT PAID IN THE SECOND OFFER IS RS 3400.

Step-by-step explanation:

The second offer is 15% off

15% of 4000 =

4000×15/100 = 600

after 15% off , the price of the watch will be

4000- 600 = rs 3400

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Answered by GulabLachman
0

Given: The list price of a watch is Rs.4000. It is available either at 25% flat discount or at successive discounts of 15% and 12%.

To find: The better offer and the amount paid in the second offer.

Explanation: List price = Rs. 4000

First case: At 25% flat discount

Discounted money

= 25% of 4000

= (25/100) × 4000

= 0.25 × 4000

= 1000

Rs. 1000 is given as discount.

Price to be paid

= Rs. (4000-1000)

= Rs. 3000

Second case: Successive discount of 15% and 12%

Discounted money at 15%

= 15% of 4000

=(15/100)× 4000

= 0.15 × 4000

= 600

Price after 15% discount

= 4000-600

= Rs. 3400

Again, a 12% discount is given on this price.

Discounted money at 12% on Rs. 3400

= 12% of 3400

= (12/100)×3400

= 0.12 × 3400

= 408

Price to be finally paid

= Rs. 3400-408

= Rs. 2992

Clearly, the second offer of successive discounts is a better offer.

Therefore, successive discounts of 15% and 12% is a better offer and the amount to be paid in the second offer is Rs. 2992.

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