Physics, asked by miksenlimbu90, 5 months ago

The load arm of a lever is 2 m long & its effort arm is 3 m long . calculate the effort required to lift a load of 21 N

options are down:-)


a.16 N

b.14 N

c.18 N

d.12 N

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Answers

Answered by Anonymous
59

Answer :

  • Effort required to lift the load to 21 N is 14 N.

Explanation :

Given :

  • Load arm of the lever, L' = 2 m
  • Effort arm of the lever, E' = 3 m
  • Load to be lifted, L = 21 N

To find :

  • Effort required to lift the load, E = ?

Knowledge required :

We know that in case of a lever ,

⠀⠀⠀⠀⠀⠀⠀⠀⠀L × L' = E × E'

Where,

  • L = Load to be lifted
  • E = Effort required to lift the load
  • L' = Load arm or the lever
  • E' = Effort arm of the lever

From the above equation, we get :

⠀⠀=> L = (E × E')/L'

⠀⠀=> L/E = E'/L'

⠀⠀⠀⠀∴ Load/Effort = Effort arm/Load arm

Solution :

By using the relation between load & Effort and Load arm & and Effort arm, we get :

⠀⠀=> L/E = E'/L'

⠀⠀=> 21/E = 3/2

⠀⠀=> 21/E × 2 = 3

⠀⠀=> 42/E = 3

⠀⠀=> 1/E = 3/42

⠀⠀=> 1/E = 1/14

⠀⠀=> 14 = E

⠀⠀⠀⠀⠀⠀⠀∴ Effort = 14 N

Therefore,

  • Effort required to lift the load, E = 14 N

Answered by panashyadav
2

EFFORT IS 14N......... IS YOUR ANSWER MATE.

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