The load arm of a nutcracker is 2 cm. the effort arm of it is 6 cm. If the nut is of 20 kgf, find the effort required to crack it.
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the handle of a nut cracker is 18 ck long and the nut is placed 2 cm from its hinge . if the force of 36 kg will be cracked . calculate the force which has to applied at the end of the handle to crack the nut .
Explanation:
load arm = 2 cm
load = 36 kg
effort = ?
effort arm = 18 cm
2×36 = effort × 18
effort = 2×36/18 = 4kgf
The force to be applied at the end of the handle to craked the nut is 4 kgf
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