The load, L, that a beam can support varies directly with the square
of its vertical thickness, h. A beam that is 5 inches thick can
support a load of 2000 pounds. How much weight can a beam hold
that is 9 inches thick?
Answers
Answered by
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L(h) = k * h²
The constant, k can be found with given values of the load
(2000 pounds) and thickness (5 inches). 2000 = k (5²
) Solve: k = 80. Our
equation becomes: L(9) = 80 (9²
) Solve: The load with a 9 inch board
will be 6480 pounds.
NightHawk:
Thank you :D
Answered by
0
We have given that L ∝ h²
So, L = kh² [puting a constant]
Case 1 Arise:
2000 = k × (5)²
k = 2000/25
k= 80
Case 2 Arises:
L = kh²
L = 80 × (9)²
L = 80 × 81
L= 6480 pounds
So, L = kh² [puting a constant]
Case 1 Arise:
2000 = k × (5)²
k = 2000/25
k= 80
Case 2 Arises:
L = kh²
L = 80 × (9)²
L = 80 × 81
L= 6480 pounds
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