The locus of a point which is at a distance of 3 units above x- axis is 1) (x,3) 2) (3,y) 3) (3,1) 4) (x,-3)
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Given : a point which is at a distance of 3 units above x- axis
To Find : locus of point
1) (x,3)
2) (3,y)
3) (3,1)
4) (x,-3)
Solution:
A line y = k is at a distance of | k | from x axis
Hence line
y = ±3 is at a distance of 3 from x axis
Any point of line y = ±3 is of form
(x , ±3)
(x , 3) is above x axis and (x , - 3) is below x axis
Hence The locus of a point which is at a distance of 3 units above x- axis is
( x , 3)
Correct option is 1) ( x , 3)
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