Question

The locus of a point which is collinear with the points (3,4) and (-4,3) is
a) 2x + 3y - 12 = 0
b) 2x + 3y + 12 = 0
0 3x + 2y + 12 = 0
d) x-7y + 25 = 0
solution plzz​

Answer 1

Answer:

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Answer 2

Answer:

Let an arbitrary point be P(x,y).

Since P(x,y),A(3,4),B(−4,3) are collinear, hence they must lie on a single line.

Thus the equation of the line is given by

y−4/x−3 = y-3/x+4

(x+4)(y−4)=(y−3)(x−3)

xy−4x+4y−16=xy−3y−3x+9

x−7y+16+9=0

x−7y+25=0.

D is the correct answer.......

hope it helps you......