Question

The locus of a point which is equidistant from two points (−4,2) and (6,6) is

Answer 1

Step-by-step explanation:

Let the point be (h,k).

Given:

Distance of point from A=Distance of point from B

⟹

(h+3)

2

+(k−2)

2

=

h

2

+(k−4)

2

⟹(h+3)

2

+(k−2)

2

=h

2

+(k−4)

2

⟹h

2

+6h+9+k

2

−4k+4=h

2

+k

2

−8k+16

⟹6h−4k+13=−8k+16

⟹6h+4k=3

Replacing h with x and k with y:

Answer 2

Answer:

hope it's helps you dear