Question

The locus of centre of a circle of radius 2 which rolls on the outside of the circle x^2+y^2+3x-6y-9=0 is



(a)x^2+y^2+3x-6y+5=0



(b)x^2+y^2+3x-6y-31=0



(c)x^2+y^2+3x-6y+29/4=0



(d)x^2+y^2+3x-6y-5=0

Answer 1

Answer:

2g=3

2f=-6

c=-9

g=3/2

f=-3/2

Step-by-step explanation:

(x-3/2)^2+(y+3/2)^2=4