Question

The locus of foot of perpendicular from focus of the hyperbola

Answer 1

Answer:

Locus of the feet of the perpendicular drawn from focus of the hyperbola x2/a2 – y2/b2 = 1 upon any tangent is its auxiliary circle i.e. x2 + y2 = a2 and the product of the feet of these perpendiculars is b2. A rectangular hyperbola circumscribing a triangle passes through the orthocentre of this triangle