Question

The locus of the centre of the circle such that the point (2, 3) is the midpoint of the chord 5x+2y=18 is​

Answer 1

Step-by-step explanation:

Given The locus of the centre of the circle such that the point (2, 3) is the midpoint of the chord 5x + 2y = 18 is

• Now in a given circle there is a chord. So for 5x + 2y = 18, we need to find the locus of the centre of the circle. So the midpoint is (2,3). So the centre of the circle is (-a, -b)
• So the slopes are m1 and m2.
• So m1 = - 5/2
• Also m2 is a slope perpendicular from the centre. So m2 = 2/5
• Now we have the equation y – y1 = m (x – x1)
•                                   So y – 3 = 2/5 (x – 2)
•                                 So 5y – 15 = 2x – 4
•                                     5y – 2x – 15 + 4 = 0
•                                     2x – 5y + 11 = 0 will be the equation

Reference link will be

https://brainly.in/question/3117262