The locus of the centre of the circle which cuts off
intercepts of length 2a and 2b from x-axis and y-axis
respectively, is
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0
Answer:
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Answered by
1
Step-by-step explanation:
For the locus of the centre,
(α−0)
2
+(β−0)
2
=
a
2
+b
2
α
2
+β
2
=a
2
+b
2
so locus is,
x
2
+y
2
=a
2
+b
2
solution
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