The locus of the equation (x2 - a?)2 + (y2 - 62)2 = 0, ab not equal to 0 contains a) A unique point c) Four points b) Two points d) Infinitely many points If the
Attachments:
Answers
Answered by
1
Answer:
Correct options are B) and C)
Given equation of circle is x
2
+4x+(y−3)
2
=0,AM=2AB
B is the mid-point of AM
⇒B=(
2
h
,
2
k+3
) lies on the circle
equation of circle is x
2
+4x+(y−3)
2
=0
Let x=
2
h
,y=
2
k+3
∴
4
h
2
+2h+(
2
k+3
−3)
2
=0
4
h
2
+2h+
4
k
2
−6k+9
=0
∴k
2
+h
2
+8h−6k+9=0
∴ locus of M is x
2
+y
2
+8x−6y+9=0
Similar questions