Question

The locus of the equation x² + y^2 +z^2 +1
= 0 is
b. a degenerated set
a. an empty set
c. a sphere
d. a pair of planes​

Answer 1

Answer:

Centre and radius of the given sphere are (0,0,0) and 3 respectively.

Now the perpendicular distance between centre of sphere to the given plane is given by,

d=∣  

3  

2

+4  

2

+5  

2

 

​  

 

−5

​  

∣=1/  

2

​  

 

Therefore radius of the circle in which the given sphere and plane cut is

=  

3  

2

−(1/  

2

​  

)  

2

 

​  

=  

2

17

​  

 

​  

Step-by-step explanation:

Answer 2

Answer:

17

Step-by-step explanation:

hope it will help you buddy