The locus of the foot of perpendicular drawn from the centre of the ellipse x² + 3y² = 6 on any tangent to it is
(a) (x² + y²)² = 6x² + 2y²
(b) (x² + y²)² = 6x² - 2y²
(c) (x² - y²)² = 6x² + 2y²
(d) (x² - y²)² = 6x² - 2y²
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Ans is A. I hope this will help you. If you are finding difficulty in questions involving finding locus, refer coordinate geometry by SL Loney for practice.
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