Question

The locus of the point which is at a distance 5 units from (-3, 4) is​

Answer 1

Let an arbitrary point be P(x,y)

Then the distance of the point P from the point A(−2,3) is

d= (x+2) 2 +(y−3) 2

d 2 =(x+2) 2 +(y−3) 2

Now the distance is given to be 5,

Hence,

(x+2) 2 +(y−3) 2 =25x 2 +y +4x−6y+4+9

=25x 2 +y 2 +4x−6y+13

=25x 2 +y 2 +4x−6y−12=0.

Hope it helps you.