The locus of the point which is at a distance 6 units from y-axis is
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Answer:
point is at a distance of 6 units from y axis
as its perpendicular distance
as x axis is perpendicular to y axis
so point is at a line parallel to x axis at a distance 6 units
that is points are at x= +-6 as x coordinate can be 6 or -6
locus of point x = +-6
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Given :
Distance = 6 units
To Find:
The locus of the point which is at a distance 6 units from y-axis
Solution:
Let our point be (x,y)
Distance of any point from y-axis = magnitude of its x coordinate
From the question we have,
Distance of any point from y-axis =6
Which implies that,
∣x∣=6
Now squaring each side we get
x²=6²
which can be re-written as
x² - 36 = 0
The locus of the point which is at a distance 6 units from y-axis is
x² - 36 = 0
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