The locus of the point x = 2(cost + sint),
y = 5(cost - sint) is
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Answered by
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Ellipse
Given, x=2(cost+sint)
⇒
2
x
=cost+sint ...(i)
And y=5(cost−sint)
⇒
5
y
=cost−sint ...(ii)
Then (
2
x
)
2
+(
5
y
)
2
=(cost+sint)
2
+(cost−sint)
2
=cos
2
t+sin
2
t+2cost.sint+cos
2
t+sin
2
t−2cost.sint
=2(cos
2
t+sin
2
t)
=2
Hence, (
2
x
)
2
+(
5
y
)
2
=2
4
x
2
+
25
y
2
=2
8
x
2
+
50
y
2
=1
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