Math, asked by swarnalaxmi, 1 year ago


the locus of the vertices of family of parabola y = a^3 x^2 /3 + a^2 x/2 -2a is

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Answered by kaira6
2

y =  \frac{ {a}^{3} {x}^{2}  }{3}  +  \frac{ {a}^{2}x }{2}  - 2a \:  comma \: a =e \: r \: comma \: x \: e \: r
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