Question

The locus represented by the equation
x^2 + 4x + 2y – 8 = 0 is
(answer my question)​

Answer 1

Answer:

x^2+4x+2y-8=0

x^2+4x+2y=0+8

x^2+4x+2y=8

x^2+4x=8-2y

x^2+x=8-2y/4

1x^2=8-2y/4

x^2=8-2y/4×1

x^2=8-2y/4

y=1 mane pare

x^2=8-2(1)/4

x^2=16/4

x^2=4

x^2=√2