the logarithmic form of ax =N is
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Answer:
Given :- The logarithmic form of a^x = N is :-
A) a = logxN
B) x = logaN
C) N=logax
D) N=logxa
Solution :-
we know that,
\begin{gathered}\bf\: if\:{a}^{n}=x,\\\bf\: then\: ,\\\bf log_{a}(x) = n\end{gathered}
ifa
n
=x,
then,
log
a
(x)=n
therefore, we can conclude that,
\begin{gathered} \rightarrow \: {a}^{x} = n\\\rightarrow \boxed{\bf \: x = log_{a}(n) (b)(ans.)}\end{gathered}
→a
x
=n
→
x=log
a
(n)(b)(ans.)
Learn more :-
● \orange{\bold{Product\:Rule\:Law:}}ProductRuleLaw:
loga (MN) = loga M + loga N
● \pink{\bold{Quotient\:Rule\:Law:}}QuotientRuleLaw:
loga (M/N) = loga M - loga N
● \green{\bold{Power\:Rule\:Law:}}PowerRuleLaw:
IogaM^(n) = n Ioga M
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