Question

The logic behind following code is
(2M)
for(i=0;i<=3;i++)
{
for(i=0;j<=3;j++)
if(i==1)
{
ab[i][j]=0;
else
{
ab[i][]=1;
}​

Answer 1

(2M)

(2M)for(i=0;i<=3;i++)

(2M)for(i=0;i<=3;i++){

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1)

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1){

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1){ab[i][j]=0;

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1){ab[i][j]=0;else

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1){ab[i][j]=0;else{

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1){ab[i][j]=0;else{ab[i][]=1;

(2M)for(i=0;i<=3;i++){for(i=0;j<=3;j++)if(i==1){ab[i][j]=0;else{ab[i][]=1;}