Question

The logical address space in a computer system consists of 128 segments. Each [03] segment can have up to 32 pages of 4K words in each. Physical memory consists of 4K blocks of 4K words in each. Formulate the logical and physical address formats.

Answer 1

Answer:

The logical address space has 128 segments x 32 pages x 4K words: 128 x 32 x 4 x 210 = 27 x 25 x 22 x 210 = 224 so we require 24 bits.

Explanation:

Physical memory has a 4K block x 4K word address space: 4 x 210 x 4 x 210 = 22 x 210 x 22 x 210 = 224 so we need 24 bits.

The two address spaces are the same size.

For logical address space, the address format would be:

7 bits for segment addressing

5 bits for page addressing

12 bit word addressing

23...17 - 16...12 - 11...0 segment - page - word

For physical address space, the address format would be:

12 bit block addressing

12 bit word addressing

word - block 23...12 - 11...0

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