Question

The logs are piled such that each row is 2 less than the one below. If the
there are 30 logs at bottom and the top most is 1, how man
y logs are there
in all?​

Answer 1

Answer:

240 logs

Step-by-step explanation

given in the problem

n = 15

d = 2

solve

Sn = n/2 (2a1 +(n - ) d

Sn = 15/ 2 (2 (2) + ( 15 - 1) 2)

Sn = 7 5 ( 4 + 14) (2)

Sn = 240 logs.

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Answer 2

Answer:

This situation is impossible.

Step-by-step explanation:

• Each row's log number is 2 less than the one in the below.
• The one at bottom has 30 logs ,i.e.,an even number of logs.
• Now,as we go above the no. of logs get decreased by 2,i.e.,an even number.
• Thus,in the top most row we should also have an even number of logs since even subtracted by even is even only.
• But it is given the top most row has 1 log,that is ,odd numbered.
• Hence,this situation is impossible.