Question

The long and short hands of a clock are 6 cm and 8 cm long respectively.Find the sum of the distances travelled by their tips in one day?[ Take π=22/7]
(class 10 CBSE SAMPLE PAPER 2017-18 MATHS)

Answer 1

Solution:

In 1 day, i.e 24 h short (hour) hand of the clock make 2 revolutions and long (minute) hand makes 24 revolutions.

In 1 revolution distance travelled by the tip of hour hand= circumference of circle of radius 6 cm
= 2πr = 2×(22/7)(6)

In 1 revolution distance travelled by the tip of minute hand= Circumference of circle of radius 8 cm
= 2πr = 2×(22/7)(8)

Sum of distances travelled by tips of both hand in one day =2× 2×(22/7)(6) +24× 2×(22/7)(8)

= 2× 12× 22/7 + 24× 2×22/7×8

= 2(22/7) (12+24×8)

= 2(22/7) (12+192)

= 2(22/7)(204)

= (44×204)/7

= 44× 29.14285

= 1282.285= 1282.29 cm (approx)

Hence, the sum of the distance travelled by their tips in one day is  1282.29 cm (approx)


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Answer 2

Answer:

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