Question

the longest side of a right angled triangle is 125 M and one of the remaining two sided is 100 m Find its area by heron 's formula

Answer 1

$1875 \sqrt{4}$
is the area of the triangle

Answer 2

Answer:

The area of the triangle is 4878.90 meter square.

Step-by-step explanation:

Given : The longest side of a right angled triangle is 125 M and one of the remaining two sided is 100 m.

To find : The area of the triangle?

Solution :

Formula to find area of triangle is  

$A= \sqrt{s(s - a)(s - b)(s - c)}$

Where, s is the semi perimeter,

$s=\frac{a+b+c}{2}$

a=125 ,b=100, c= 100 cm sides of the triangle

Substituting in the formula,

$s=\frac{125+100+100}{2}$

$s=\frac{325}{2}$

$s=162.5$

$A= \sqrt{s(s - a)(s - b)(s - c)}$

$A=\sqrt{162.5(162.5 - 125)(162.5 - 100)(162.5 - 100)}$

$A= \sqrt{162.5 \times 37.5 \times 62.5 \times 62.5}$

$A= \sqrt{23803710.93}$

$A=4878.90 m^2$

Therefore, The area of the triangle is 4878.90 meter square.