Question

The longest side of an isosceles triangle is 4cm more than twice of each equal side. Find the length of the longest side, if the perimeter is 28 cm.

Answer 1

Answer:

Length of longest side is 16 cm

Step-by-step explanation:

Let each equal side have a length x cm.

⇒ longest side has a length (2x + 4) cm

Perimeter of the triangle

= sum of lengths of the three sides

= (x + x + 2x + 4) cm

= (4x + 4) cm

This perimeter is given as 28 cm

⇒ (4x + 4) = 28

⇒ 4(x+1) = 4(7)

⇒ (x + 1) = 7

⇒ x = 7 - 1 = 6

⇒ 2x + 4 = 2(6) + 4 = 16

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