Math, asked by anikarose, 1 year ago

The longest side of right angled triangle is 125cm and the remaining two sides is 100cm. Find its area using heron's formula.

Answers

Answered by shivaponnala
1

herons formula is s=a+b+c/2
125+100+100+/2=162.5
s=162.5
area=square root of s(S-a)(s-b)(s-c)

Answered by Anonymous
6

\textbf{\underline{\underline{According\:to\:the\:Question}}}

\textbf{\underline{Largest\;side\;of\;Triangle}}

= 125 m

\textbf{\underline{One\;side}}

= 100 m

\textbf{\underline{Contradiction}}

Perpendicular = 100 m

\textbf{\underline{Using\;Pythagoras\;Theorem}}

(H)² = (B)² + (P)²

(125)² = (B)² + (100)²

15625 = (B)² + 10000

(B)² = 15625 - 10000

(B)² = 5625

B = √5625

\textbf{\underline{Base\;of\;third\;side}}

= 75 m

\textbf{\underline{Semi\;Perimeter}}

\tt{\rightarrow\dfrac{a+b+c}{2}}

\tt{\rightarrow\dfrac{125+100+75}{2}}

\tt{\rightarrow\dfrac{300}{2}}

s = 150 m

\textbf{\underline{Using\;Herons\;Formula}}

\tt{\rightarrow\sqrt{s(s-a)(s-b)(s-c)}}

\tt{\rightarrow\sqrt{150\times(150-125)(150-100)(150-75)}}

\tt{\rightarrow\sqrt{150\times 25\times 50\times 75}}

\tt{\rightarrow\sqrt{14062500}}

= 3750 m²

\Large{\boxed{\sf\:{Area\;of\;Triangle=3750\;m^2}}}

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