The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.
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To calculate the frequency of each transition and energy difference between two excited states λ1 = 589 nm = 5.89X10-9m
therefore v1=c/ λ1 = 3x108/589x10-9 = 5.093x1014/sec
λ2 = 589.6nm = 589.6x10-9m
therefore v2 = c/ λ2 = 3x108/589.6x10-9
= 5.088x1014/sec
ΔE=E2-E1 = h(v2-v1)
= (6.626x10-34)(5.093x-5.088)x1014
= 3.31x10-22J is the frequency of each transition and energy difference between two excited states.
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