Math, asked by caenadi, 3 months ago

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 log StartFraction I Over I 0 EndFraction, where I 0 = 10 Superscript negative 12 and is the least intense sound a human ear can hear. Jessica is listening to soft music at a sound intensity level of 10-9 on her computer while she does her homework. Braylee is completing her homework while listening to very loud music at a sound intensity level of 10-3 on her headphones. How many times louder is Braylee’s music than Jessica’s?

Answers

Answered by amitnrw
29

Given : The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter,

L = 10 log (I / I₀)   I₀ = 10⁻¹²  

Jessica is listening to soft music at a sound intensity level of 10⁻⁹ on her computer while she does her homework.

Braylee is completing her homework while listening to very loud music at a sound intensity level of 10⁻³ on her headphones.

To Find : How many times louder is Braylee’s music than Jessica’s?

Solution:

L = 10 log (I / I₀)   I₀ = 10⁻¹²  

Jessica is listening to soft music at a sound intensity level of 10⁻⁹

=> L = 10 log ( 10⁻⁹  / 0⁻¹² )

=> L = 10 log (10³ )

=> L = 10 * 3  

=> L = 30 Db

Braylee is   listening to very loud music at a sound intensity level of 10⁻³

=>  L = 10 log ( 10⁻³  / 0⁻¹² )

=> L = 10 log (10⁹ )

=> L = 10 * 9  

=> L = 90 Db

90 = 3 * 30

Braylee’s music is 3 times louder than jessica

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Answered by kaleb18721
55

Answer:

B. 3 times louder

Step-by-step explanation:

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