Question

the lower end of a capillary tube is dipped in water. Water rises upto height 10cm. The tube is broken upto 8cm. Then angle of contact will be​

Answer 1

Explanation:

The lower end of a glass capillary tube is dipped in water rises to a height of 8 cm the tube is then broken at a height of 6 cm. The height of water column and angled as contact will be

(A) 6 cm ∙ sin–1 (3/4)

(B) 6 cm ∙ sin–1 (4/5)

(C) 6 cm ∙ cos–1 (3/4)

(D) 6 cm ∙ sin–1 (1/2)

Answer 2

The angle of contact is 53.13°.

Explanation:

Given that,

Height of water= 8 cm

Capillary tube is broken at a height = 10 cm

We need to calculate the angle of contact

Using formula of angle of contact

$h = \dfrac{2S\cos\theta}{r\rho g}$

$\dfrac{h}{\cos\theta} = a$

Here, $a = \dfrac{2S}{r\rho g}$

a is a constant.

$\dfrac{h}{\cos\theta}=\dfrac{h}{\cos\theta}$

Here, $\theta=0^{\circ}$

$\dfrac{10}{\cos0^{\circ}}=\dfrac{6}{\cos\theta}$

$\cos\theta=\dfrac{6\cos0}{10}$

$\theta=\cos^{-1}(\dfrac{6\cos0}{10})$

$\theta=53.13^{\circ}$

Hence, The angle of contact is 53.13°.

Learn more :

Topic :

https://brainly.in/question/3050410