Question

the lower end of a capillary tube is dipped in water .Water rises upto height 10 cm .The tube is broken upto 8 cm .Then new angle of contact will be
(1). 53°
(2).37°
(3).30°
(4).0°​

Answer 1

As radius and content of tube is same so T,r,g,ρis cons tan t Therefore

hcosθ=constant

h1h2=cosθ1cosθ2

108=cos0cosθ2 cosθ2=810=0.8

θ2=36.86=37∘