Question

The lower end of a capillary tube of diameter 2.00 mm is dipped 8 cm below the water surface in a beaker. what is the pressure required in the tube in order to blow a hemispherical bubble at its end in water?
density of water= 10^3 kg/m^3
surface tension of water= 7.3×10^-2 N/m^2
atmospheric pressure= 1.01× 10^5 pa​

Answer 1

Answer:

The excess pressure in a bubble of gas inn a liquid is given by

r

25

we know that

P

0

=P

a

+hdg

P

0

=1.01×10

5

+0.08×1000×9.80

P

0

=1.01784×10

5

pa

Now P

i

=P

0

+

r

25

P

i

=P

0

+

r

25

P

i

=1.01784×10

5

+

10

−3

2×7.9×10

−2

p

i

=1.02×0

5

Pa

Explanation:

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