The lower face of an aluminium cube, of side 10cm, is riveted to the floor. A shearing modulus of aluminium is 25×10^9N/m^2, find the displacement of the upper edge of the cube.
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G (shear modulus)=f•l/A ∆l
25 × 10^9=1000×100×100×10/10×10×∆l× 100
(((Converting into s.i units)))
∆l= 10^4/10^9×25
∆l= 4 × 10^-7
25 × 10^9=1000×100×100×10/10×10×∆l× 100
(((Converting into s.i units)))
∆l= 10^4/10^9×25
∆l= 4 × 10^-7
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