Question

the lower part of a circus tent is a right circular cylinder and its upper part is right circular cone the diameter of the base of the 10th is 56 cm and height of the cone is 15 M the total height of the 10th is 60 M how many square metres of Canvas is required for the 10th find the value of a space in tent

Answer 1

Answer:

10715.3 $m^2$ canvas is required and Space of tent is 123200 $m^3$  

Step-by-step explanation:

Given: Circus tent has Cylinder in base and cone on top

           Diameter of Base = 56 m, Height of cone = 15 m, Total Height = 60 m

To find: Area of Canvas for tent and volume of space in tent

Diameter of Base = 56 m

⇒ Radius of Base = $\frac{56}{2}$ = 28 m

⇒ Radius of cylinder and cone , r = 28 m

Height of cone , H = 15 m

Slant Height of Cone , l  given by

$l^2=H^2+r^2$

$l^2=15^2+28^2$

$l^2=225+784$

$l^2=1009$

$l=\sqrt{1009}$

$l=31.7647603\:m$

Height of the cylinder, h = Total Height of tent - height of cone

                                     h = 60 - 15

                                     h = 45 m

Area of Canvas required for tent

= Curved Surface Area of Cylinder + Curved Surface are of cone

= $2\pi rh + \pi rl$

= $2\times\frac{22}{7}\times28\times45+\frac{22}{7}\times28\times(31.7647603)$

= $2\times\times22\times4\times45+22\times4\times(31.7647603)$

= $7920+ 2795.29386$

= 10715.2939 $m^2$

Space in Tent = Volume of cylinder + volume of cone

                       = $\pi r^2h+\frac{1}{3}\pi r^2H$

                       = $\pi r^2(h+\frac{1}{3}H)$

                       = $\frac{22}{7} 28^2(45+\frac{1}{3}15)$                        

                       = $22\times4\times28(45+5)$  

                       = $22\times4\times28\times50$

                       = 123200  $m^3$

Therefore, 10715.3 $m^2$ canvas is required and Space of tent is 123200 $m^3$

Answer 2

Answer:

hope it helps you......