the lower part of a circus tent is cylindrical and the upper part is conical. the radius of the base of the tent is 28 m and the height of the cylindrical part is 15m .if the slant height of the conical part is 53m .find the canvas required for the tent.
Answers
Answer:
7304 m²
Step-by-step explanation:
Given---> Radius of base of tent = 28m
Height of cylindrical part = 15m
Slant height of cone = 53m
To find ---> Canvas required to make the tent
Solution---> First we find curved surface area of cylindrical part and conical part of tent .
Curved surface area of cylindrical part= 2πrh
= 2 × 22/7 × radius of base × height of cylindrical
part
= 2 × (22 / 7) × 28 × 15
= 2 × 22 × 4 × 15
= 44 × 60
= 2640 m²
Curved surface area of cone = π r l
= ( 22 / 7 ) × ( radius of base ) × Slant height
= ( 22 / 7 ) × 28 × 53
= 22 × 4 × 53
= 88 × 53
= 4664 m²
Area of canvas required for making tents
= curved surface Area of cylindrical part + curved surface area of conical part
= 2640 + 4664
= 7304 m²
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