The lower part of a circus tent is cylindrical and the upper part is conical .the diameter of the base of the tent is 56mand height of the cylindrical part is 15m.The total height of the tent is 60m.How much canvas is required for the tent.
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4660 + 2640 = 7304 csa of cone + csa of cylinder
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r =56/2=28m
l= root of( r square + h square)
= root of (28 square + 60 square)
= root of (4384)
=66.21 (approx)
area of cone (curved) = pi x r x l
= 22/7 x 28m x 66.21m
total sheet required = 5826.48 (approx)
i think it helpps u so mrk as brainlist
l= root of( r square + h square)
= root of (28 square + 60 square)
= root of (4384)
=66.21 (approx)
area of cone (curved) = pi x r x l
= 22/7 x 28m x 66.21m
total sheet required = 5826.48 (approx)
i think it helpps u so mrk as brainlist
shubhadachawde:
but it's ans is 7304 ur ans is wrong
no it checked
if any wrong see in my ans
s its answ is 7304
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